Cage Splitting
A cage crossing a house boundary is cut into two parts, each with its own known total.
How it works
- 1Work out a region's leftover cells the usual way — subtract the cages sitting wholly inside it from 45, 90 or 135.
- 2Now check whether those leftover cells all belong to ONE cage. If they do, you have just split that cage: its portion inside the region has a known total.
- 3That matters because cells of a single cage hold distinct digits by the cage rule — even when they span two houses — so the combination reasoning applies to the split part.
- 4Example: columns 4 and 5, which hold 90 between them. Every cage inside the pair straddles both columns, so neither column on its own has anything whole to subtract — each sees all nine of its cells left over, and says nothing at all.
- 5The band's whole cages come to 75 across sixteen cells. The two cells left over are the band half of a 4-cell cage totalling 25, the other half sitting in column 6.
- 6Two leftovers is one too many for the band's own innie rule, which places a lone cell and nothing else, and its outie form wants a single cell lying outside, where this cage leaves two.
- 7That rule then stops, and for a reason: cells left over from a BAND sit in different houses, so in general nothing forces their digits to differ — and differing digits are exactly what the combination table assumes. These two are one cage's cells, and a cage never repeats a digit, so the table applies to them after all.
- 8They add to 90 − 75 = 15, so they are 6+9 or 7+8 and nothing else — 1 through 5 go from both. Reading the cage on its own could never have said that: 25 across four cells admits every digit from 1 to 9.